The following table shows a sample of the amount spent for lunch by 8 students
Lunch Spending ($) = xi |
||||
28 |
||||
10 |
||||
1 |
||||
15 |
||||
8 |
||||
6 |
||||
10 |
||||
6 |
||||
A = 4
B = 3
C = 2
D = 1
F = 0
George’s transcript shows the following grades.
Class |
Units |
Grade |
||
English |
3 |
B |
||
Biology |
4 |
C |
||
Geography |
3 |
B |
||
Weightlifting |
1 |
A |
||
Statistics |
4 |
A |
||
German |
5 |
F |
||
Calculate George’s GPA.
Problem 1
i)
Sample mean=Sum of observations/Number of observations
Sample mean=(28+10+1+15+8+6+10+6)/8=$10.50
ii)
Let us find the frequency of each amount spent
Amount Spent | Frequency |
1 | 1 |
6 | 2 |
8 | 1 |
10 | 2 |
15 | 1 |
28 | 1 |
Highest frequency is 2.
It happens two times i.e. for amount spent of $6 and $10
So, data has two modes namely $6 and $10.
We can say that data is Bi-modal.
iii)
First we arrange data in ascending order.
1, 6, 6, 8,10, 10, 15, 28
Since number of observations is even, we take average of two middle most terms (4th and 5th) i.e. 8 and 10 to calculate median.
Median=(8+10)/2=$9
Problem 2
Georges GPA will be weighted average of George's score
Class | Units | Grade | Grade score | Unit*Grade Score |
English | 3 | B | 3 | 9 |
Biology | 4 | C | 2 | 8 |
Geography | 3 | B | 3 | 9 |
Weightlifting | 1 | A | 4 | 4 |
Statistics | 4 | A | 4 | 16 |
German | 5 | F | 0 | 0 |
Sum | 20 | 46 |
GPA=46/20=2.30
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