Sophie has $ 76, the price of gasoline is $4 per gallon and the price of food is $20 per meal. Use the information in the following table to analyze her choice.
Gas |
Marginal Utility of Gas |
Marginal Utility of Gas over the price of Gas |
Food |
Marginal Utility of Food |
Marginal Utility of Food over the price of Food |
1 |
120 |
1 |
600 |
||
2 |
116 |
2 |
560 |
||
3 |
112 |
3 |
500 |
||
4 |
100 |
4 |
460 |
||
5 |
92 |
5 |
360 |
||
6 |
80 |
6 |
320 |
What is the best combination of food and gasoline that maximizes her utility?
4 units of Gas and 3 units of food |
||
4 units of Gas and 4 units of food |
||
5 units of Gas and 3 units of food |
||
5 units of Gas and 5 units of food |
Optimal is attained where MUx/Px = MUy/Py and Px.X + Py.Y = Income
4X + 20Y = 76
X is the units of Gas
Y is the units of Food
Combination of output where MUgas/Pgas = MUfood/Pfood are (1 Gas; 1 Food), (3 Gas; 2 Food), (4 Gas, 3 Food), (5 Gas, 4 Food)
Cost of (1 Gas; 1 Food) = 4 x 1 + 20 x 1 = 4 + 20 = 24 < 76
Cost of (3 Gas; 2 Food) = 4 x 3 + 20 x 2 = 12 + 40 = 52 < 76
Cost of (4 Gas; 3 Food) = 4 x 4 + 20 x 3 = 16 + 60 = 76 = Income
Answer is; 4 units of Gas and 3 units of food
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