Based on market research data, you have derived the following price-volume function:
x (p) = 23.600 e-0,5p
p1 = $1.50 USD
p2 = $2.80 USD
p3 = $3.60 USD
p4 = $5.00 USD
Ans. Demand function,
x = 23.6e-0.5p
Differentiating with respect to p, we get,
dx/dp = -0.5*23.6e-0.5p
=> Price elasticity of demand, E = dx/dp * p/x
E = -11.8e-0.5p * p/x
a) At p1 = $1.5, x = 11.15
=> E = -11.8e-0.5*1.5*1.5/11.15 = -0.75
At p2 = $2.80 , x = 5.82
=> E = -11.8e-0.5*2.8*2.80/5.82 = -1.4
At p3 = $3.60, x = 3.9
=> E = -11.8e-0.5*3.6*3.6/3.9 = -1.8
At p4 = $5, x = 1.94
=> E = -11.8e-0.5*5*5/1.94 = -2.5
b) Total Revenue, TR = P*x = 23.6e-0.5p*p
For optimal revenue,
Differentiate TR with respect to p
=> dTR/dp = 23.6e-0.5p - 0.5*p*23.6e-0.5p = 0
=> p = $2
Thus, revenue is optimal at p = $2
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