A | B | C | |
Initial cost | $1500 | $900 | $1200 |
Annual benefit | $800 | $200 | $180 |
Salvage value | $500 | $900 | $0 |
Life in years | 2 | 3 | infinite |
MARR | 10% | 10% | 10% |
Assume that alt. A will be needed for 6 years. The NPW of alt. A is _____.
$1100 |
||
$1342 |
||
$600 |
||
$757 |
Answer is $ 757.
The explanation is as follows:
Year | Cashflows | PVF @ 10% | Present Value | ||||
0 | -1500 | 1.000 | -1500.00 | ||||
1 | 800 | 0.909 | 727.27 | ||||
2 | -200 | 0.826 | -165.29 | ||||
3 | 800 | 0.751 | 601.05 | ||||
4 | -200 | 0.683 | -136.60 | ||||
5 | 800 | 0.621 | 496.74 | ||||
6 | 1300 | 0.564 | 733.82 | ||||
Present worth of Cash flows | 756.99 | ||||||
Note: In year 2 and 4, the cash flows is computed by adding the salvage value and deducting the initial investment to be made again. | |||||||
Note: In Year 6, salvage value shall be added in the annual benefit to compute the cash flows |
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