Let,
Score of the candidate be x
Mean, M = 500
Standard deviation, s = 50
Probability that score of the randomly selected applicant is between 438 and 604
P( 438 < x < 604)
=> P ( (438-M)/s < (x-M)/s < (604-M)/s))
=> P( (438-500)/50 < z < (604-500)/50)
=> P(-1.24 < z < 2.08) = P(z< 2.08) - P(z < -1.24)
=> Probability = 0.9812 - 0.1075 = 0.8737
Thus, probablity that the score of the randomly selected applicant lies between 604 and 438 is 87.37%.
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