Given,
sample size = n = 11
μ = popualation mean = 51 and
σ = population standard deviation = $7.5
a) We should be willing to make the assumption that the population is at least approximately normal.
Because the sample size is small and thus we cannot use central limit therom to obtain that the sampling distribution approximately normal.
b)
ME = margin of error = critical value * σ / SQRT(n)
critical value for α = 95 % = ± 1.96 ( from statistical table for z test )
and σ / SQRT(n) = 2.2613
ME = (1.96 * 2.2613)
= $4.43
c)
ME = margin of error = critical value * σ / SQRT(n)
critical value for α = 99 % = ± 2.58 ( from statistical table for z test )
and σ / SQRT(n) = 2.2613
ME = (2.58 * 2.2613)
= $5.83
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