A mechanical robot is part of a welding operation on an automobile assembly line costs $750,000. Its annual O& M cost will be $10,000 and its expected life is only 6 years, while its estimated salvage value when retired is anticipated to be approximately $40,000. The robot will replace welding operation labor cost. If the interest rate is 20% what annual labor savings must be realized over the robot’s life to justify the expenditure?
Initial Cost = $750,000
Annual O & M cost = $10,000
Life = 6 years
Estimated Salvage Value = $40,000
Interest rate = 20%
What annual labor savings must be realized over the robot’s life to justify the expenditure?
Converting the initial cost into annual cost
A = P (A/P, i, n)
A = $750,000 (A/P, 20%, 6)
A = $750,000 (0.3007) = $225,525
Annual O & M Cost = $10,000
Total Annual Cost = $225,525 + $10,000 = $235,525
Converting Salvage value into annual salvage value (revenue)
A = F (A/F, i, n)
A = $40,000 (A/F, 20%, 6)
A = $40,000 (0.1007) = 4,028
Annual Worth (AEC) = $235,525 – 4,028 = $231,497
Annual labor savings of $231,497 must be realized over the robot’s life to justify the expenditure
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