This problem refers to the following game:
A |
B |
|
A |
(2, 4) |
(0, 2) |
B |
(1, 1) |
(3, 4) |
a. What are the pure-strategy Nash equilibria?
b. Is there a mixed strategy Nash equilibrium where both players mix A and B? If so, find the equilibrium. If not, explain why not.
A There are two pure strategy Nash equilibria. First is A and A. The reason is if player 1 chooses A, player 2 will also choose A because returns are higher(4 compared to 2).Similarly if 2 chooses A, 1 will choose A because returns of 4 are higher than otherwise (1).
Similarly BB is Nash equilibria since whatever 1 does it is always better for 2 to choose B if A chooses B and it is always better for 1 to choose B if 2 chooses B.
No there is not any mixed strategy as they are satisfied with AA or BB depending on which player choose What initially.
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