Investment, P = $ 10,000
Amount received,A = $ 2,775 every year
Interest rate = i%
Time, n = 5
This can be written as
This we can solve using Trial and error method.
Let us assume rate of return is 10%
The present value of cash inflow at a rate of 10% is greater than $ 10,000. Thus increase I.
Let us assume i=13%
At a rate of 13% it is less than 10,000. Thus, the required rate lies in between 10 to 13%. We can calculate the rate through linear interpolation technique as follows
Rate of Return = 12.05%
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