Suppose that you make a series of annual deposits into a bank account that pays 8% interest. The initial deposit at the end of the first year is $1,200. The deposit amounts decline by $200 in each of the next four years. How much would you have immediately after the fifth deposit?
Amount at end of first year = 1200
This amount includes the interest received in the first year. Therefore, amount deposited in the first year is 1200/1.08 = 1111.1111
Year | Amount at the beginning of year(A) | Amount deposited(B) | Total amount (C) (A+ B) | Interest amount(D) (C)*0.08 | Amount at the end of year (C+D) |
1 | 0 | 1111.111111 | 1111.111111 | 88.88888889 | 1200 |
2 | 1200 | 911.1111111 | 2111.111111 | 168.8888889 | 2280 |
3 | 2280 | 711.1111111 | 2991.111111 | 239.2888889 | 3230.4 |
4 | 3230.4 | 511.1111111 | 3741.511111 | 299.3208889 | 4040.832 |
5 | 4040.832 | 311.1111111 | 4351.943111 | 348.1554489 | 4700.09856 |
Amount immediately after the fifth deposit is 4351.94311
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