"Your company needs a machine for the next 20 years. You are
considering two different machines.
Machine A
Installation cost ($): 2,500,000
Annual O&M costs ($): 77,000
Service life (years): 20
Salvage value ($): 79,000
Annual income taxes ($): 65,000
Machine B
Installation cost ($): 1,250,000
Annual O&M costs ($): 107,000
Service life (years): 10
Salvage value ($): 46,000
Annual income taxes ($): 45,000
If your company s MARR is 14%, determine which machine you should
buy. Assume that machine B will be available in the future at the
same costs. Enter the Annual Equivalent Cost as a positive number
of the preferred machine."
Machine A | Machine B | |
Installation cost | 2500000 | 1250000 |
Annual OM costs | 77000 | 107000 |
Annual income taxes | 65000 | 45000 |
Service life | 20 | 10 |
Savage value | 79000 | 46000 |
(A/P,i,n) = i (i+1)N [ (1+i)N-1]-1
(A/F,i,n) = i[ (1+i)N-1]-1
Machine A AEC = -2500000 (A/P,14%,20) +79000 (A/F,14%,20) - 77000-65000
Machine A AEC = -377465 + 868 - 142000
Machine A AEC = -518597
Machine B AEC = -1250000 (A/P,14%,10) +46000 (A/F,14%,10) - 107000-45000
Machine B AEC = -239642 + 2379 - 152000
Machine B AEC = -389263
Select Machine B as
AEC of MAchine B > AEC of machine A
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