Two equivalent pieces of quality inspection equipment are being
considered for purchase by Square D Electric. Machine 2 expected to
be versatile and technologically advanced enough to provide net
income longer than machine 1. Assume i= 10%. Select the
best machine based on the discounted payback method. ( need more
steps )
solution
Machine 1
0=-12,000+3000(P/A,10 %,np)
np==5.37 years
Machine 2
8,000 Machine-2
0=-8,000+1000(P/A,10%,5)+3000(P/A,10%,np-5)(P/F,10%,5)= Np= 7.7years
Then choose machine 1
Year | Machine 1 | DF | PV | Cumulative NPV | Machine 2 | PV | Cumulative NPV |
0 | -12000 | 1 | -12000 | -12000 | -8000 | -8000 | -8000 |
1 | 3000 | 0.9091 | 2727.3 | -9272.7 | 1000 | 909.1 | -7090.9 |
2 | 3000 | 0.8264 | 2479.2 | -6793.5 | 3000 | 2479.2 | -4611.7 |
3 | 3000 | 0.7513 | 2253.9 | -4539.6 | 3000 | 2253.9 | -2357.8 |
4 | 3000 | 0.683 | 2049 | -2490.6 | 3000 | 2049 | -308.8 |
5 | 3000 | 0.6209 | 1862.7 | -627.9 | 6000 | 3725.4 | 3416.6 |
6 | 3000 | 0.5645 | 1693.5 | 1065.6 |
DF = 1/(1+0.1)^n , 0.1 = 10 percent interest rate, n = no of years
PV = DF*cashflow
Discounted pay back period for machine 1= 5+(627.9/(627.9+1065.6) = 5.37 years
Discounted pay back period for machine 2= 5+(308.8/(308.8+3416.6) = 5.08 years
Machine 2 has lower discounted pay back period than machine 1
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