Consider the hypothesis statement to the right. State your conclusion given thats=5.4, n=27, andα=0.05. |
H0: σ2=13.0 H1: σ2≠13.0 |
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Calculate the appropriate test statistic.
The test statistic is
nothing.
(Round to two decimal places as needed.)
It shall be noted that a chi-square test can be used to test if the variance of a population is equal to a specified value.
H0: σ2=13.0
H1: σ2≠13.0
The given information is:
s=5.4
n=27
Thus, the test-statistic
T=(n−1)*(s/σ0)^2
=(27-1)*(5.4/13)^2
=4.49 (rounded to two decimal places)
The test is two-tailed
The level of significance = 5%
The critical chi-square statistics at (5/2)% level of significance and 26 degrees of freedom is 38.89
Since the actual chi-square statistic is 4.49 is less than the critical chi-square statistic of 38.89 at a 5% level of significance (two-tailed), the null hypothesis is rejected, thereby implying that the variance is statistically significantly different from 13
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