Start the price at the number of letters in your first and last names combined for Q = 1, and then reduce the price as Q increases. ( My First name letters are 6 and the last name letters are 8 )
For costs, begin with TC = 6 at Q = 1, then you may use any numbers you like for costs. You may need to play around with the numbers to make this work out.
Show that MR = MC at profit maximization. Graph MR, MC and Price and show the profit maximizing level of output. (You don’t need to graph ATC and show the profit rectangle).
Answer;
The table:
Price | Quantity | TR | MR | TC | MC | Profit |
14 | 1 | 14 | 0 | 6 | 0 | 8 |
13 | 2 | 26 | 12 | 14 | 8 | 12 |
12 | 3 | 36 | 10 | 20 | 6 | 16 |
11 | 4 | 44 | 8 | 25 | 5 | 19 |
10 | 5 | 50 | 6 | 29 | 4 | 21 |
9 | 6 | 54 | 4 | 32 | 3 | 22 |
8 | 7 | 56 | 2 | 34 | 2 | 22 |
7 | 8 | 56 | 0 | 37 | 3 | 19 |
6 | 9 | 54 | -2 | 41 | 4 | 13 |
5 | 10 | 50 | -4 | 46 | 5 | 4 |
4 | 11 | 44 | -6 | 53 | 7 | -9 |
3 | 12 | 36 | -8 | 62 | 9 | -26 |
2 | 13 | 26 | -10 | 73 | 11 | -47 |
1 | 14 | 14 | -12 | 86 | 13 | -72 |
Profit is maximum at Q = 6 and Q = 7.
At Q = 6, MR($4) is greater than MC ($3). So, firm will produce
more till MR = MC, that is at Q = 7.
Graph:
Fom the graph, it is evident that Q = 7, P = 8. Output is where MR=MC.
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