A. |
$ 3858 |
|
B. |
$ 3658 |
|
C. |
$ 3558 |
|
D. |
$ 3758 |
Interest rate = 14%
Duration of the investment = 4 years
From the compound interest factor table, we obtain
(F/P, 11%, 4) = 1.518
(F/A, 11%, 4) = 4.710
Let the required yearly savings be 'S'
Future worth of the given investment = $15,000(F/P, 11%, 4) + S(F/A, 11%, 4) = $15,000*1.518 + S*4.710 = 22,770 + 4.71S
Required future worth = $40,000
=> 22770 + 4.71S = 40000
=> 4.71S = 17230
=> S = 17230/4.71
S = 3658
Required annual savings = $3,658
Ans: B. $3658
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