Question

A million-dollar oil drilling rig has a 6-year depreciable life and a $75,000 salvage value at...

A million-dollar oil drilling rig has a 6-year depreciable life and a $75,000 salvage value at the end of that time. Determine which one of the following methods provides the preferred depreciation schedule: DDB or SOYD. Show the depreciation schedule for the preferred method.

Homework Answers

Answer #1

SOYD method is the preferred method. Because DDB method will not reach the salvage value and will result in capital gain at the end of the life of the asset.

The depreciation schedule is given below:

Sum of the Years = N(N+1) / 2 = 6(6 + 1) / 2 = 21

Depreciable base = Cost of the asset - Salvage value = 1,000,000 - 75,000 = $925,000

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A depreciable asset is purchased for $50,000. The expected salvage value is zero at the end...
A depreciable asset is purchased for $50,000. The expected salvage value is zero at the end of it’s 8 year useful life. Compute the depreciation schedule by using double declining balance (DDB) to switch over straight line depreciation. Also, determine the book value of the asset after 6 years.
A company purchase an asset wiht 5- year depreciable life for 75,000 with no expected salvage...
A company purchase an asset wiht 5- year depreciable life for 75,000 with no expected salvage value. The company uses straight line depreciation for financial statement and uses double-declining for tax accounting. Assume a tax rate of 34% What is the value of the company's deferred tax account at the end of the second year? Correct Answer: 6120 Can you show me how to solve this problem?
A machine costing $215,000 with a four-year life and an estimated $19,000 salvage value is installed...
A machine costing $215,000 with a four-year life and an estimated $19,000 salvage value is installed in Luther Company’s factory on January 1. The factory manager estimates the machine will produce 490,000 units of product during its life. It actually produces the following units: 121,500 in 1st year, 122,900 in 2nd year, 120,900 in 3rd year, 134,700 in 4th year. The total number of units produced by the end of year 4 exceeds the original estimate—this difference was not predicted....
A machine costing $211,600 with a four-year life and an estimated $16,000 salvage value is installed...
A machine costing $211,600 with a four-year life and an estimated $16,000 salvage value is installed in Luther Company’s factory on January 1. The factory manager estimates the machine will produce 489,000 units of product during its life. It actually produces the following units: 121,600 in Year 1, 123,200 in Year 2, 121,500 in Year 3, 132,700 in Year 4. The total number of units produced by the end of Year 4 exceeds the original estimate—this difference was not predicted....
A Tank costs 90,000 $ with a life of 6 years and has no salvage value....
A Tank costs 90,000 $ with a life of 6 years and has no salvage value. It needs an annual maintenance expenditure of 1200 $ for cleaning the tank from inside arrangement. The interest rate is 12%. Calculate the following i) Present worth at zero time of the annual maintenance ii) Future worth of annual maintenance for each year of operation iii) Calculate the depreciation and asset value at the end of 4th year using straight line depreciation method
An asset will cost $1,750 when purchased this year. It is further expected to have a...
An asset will cost $1,750 when purchased this year. It is further expected to have a salvage value of $250 at the end of its five year depreciable life. Calculate complete depreciation schedules giving the depreciation charge, D(n), and end-of-year book value, B(n), for straight-line (SL), Declining Balance (DB) with a rate of d=0.25, double declining balance (DDB), and modified accelerated cost recovery (MACRS) depreciation methods. Assume a MACRS recovery period of 5 years with the following depreciation rates. Year...
Cost of asset: $10000 Useful life: 5 years Salvage Value: $2000 Depreciation Method: DDB a) What...
Cost of asset: $10000 Useful life: 5 years Salvage Value: $2000 Depreciation Method: DDB a) What is the value of α? 0.4 b) What is the amount of depreciation for the second year of use of the asset? $2400 c) What is the book value of the asset at the end of the fourth year? $2000
A depreciable asset with a three-year life has a first cost of $30,000 with a $6,000...
A depreciable asset with a three-year life has a first cost of $30,000 with a $6,000 salvage value. The machine's operating cost is $10,000 in year one, $12,000 in year two and $14,000 in year three. According to the straight line method, the depreciation charge in year 2 is closest to: A. $8,000 B. $10,000 C. $20,000 D. $22,000
Asset C3PO has a depreciable base of $24.75 million and a service life of 10 years....
Asset C3PO has a depreciable base of $24.75 million and a service life of 10 years. What would the accumulated depreciation be at the end of year five under the sum-of-the-years' digits method? (Do not round intermediate calculations.) $6.75 million. None of these answer choices are correct. $12.38 million. $18.00 million.
Declining Balance Method The cost of the asset: $6,000.00 The salvage value: $800.00 The life of...
Declining Balance Method The cost of the asset: $6,000.00 The salvage value: $800.00 The life of the asset: 5 years Calculate the Book Value to the Nearest One Dollar at End of Year 4. Please show work.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT