Suppose there are two firms and they pollute the environment. Their total abatement cost is given below.
TC(R1)=1/2(R1)^2,
TC(R2)=2/3(R2)^3/2
Suppose the government wants to reduce pollution by 12 units.
1. Find the cost-efficient way to abate 12 units of pollution. How many of these 12 units would Firm 1 abate?
2. Find the cost-efficient way to abate 12 units of pollution. How many of these 12 units would Firm 2 abate?
3. Choose all the policies below that do not achieve cost efficiency.
A. The government mandates that Firm 1 abates 6 units and Firm 2 abates 6 units.
B. The government mandates that Firm 1 abates 4 units and Firm 2 abates 8 units.
C. The government mandates that Firm 1 abates 5 units and Firm 2 abates 7 units.
D. The government mandates that Firm 1 abates 3 units and Firm 2 abates 9 units.
E. The government mandates that Firm 1 abates 7 units and Firm 2 abates 5 units.
4. What is the lowest abatement cost to society to reduce pollution by 12 units? Use 2 decimals.
5. Suppose the government wants to reduce pollution by mandating that both firms cut pollution by 6 units. What is the abatement cost of society for such a policy? Use 2 decimals.
1) If 12 units have to be abated, then
R1 + R2 = 12 ...... eq 1
and at cost efficient method, the following takes place -
MAC(R1) = MAC(R2)
dTC(R1)/dR1 = dTC(R2)/R2
R1 = R21/2 ..... equation 2
From eq 1 and eq 2
R21/2 + R2 = 12
R2 = 9
and thus, R1 = 12-9 = 3
Hence, firm 1 will abate 3 units of total
b) As already solved in part (a), that R2 = 9
thus firm 2 will abate 9 units of total 12 units.
c) All the policies except D do not achieve cost efficiency. Because at cost efficient, R2 = 9 and R1 = 3, which is present in option D.
d) Now put R1 = 3 and R2 = 9 into given cost functions as follows -
Total cost = TC1 + TC2
TC = 1/2(R1)2 + 2/3(R2)3/2
TC = 1/2(3)2 + 2/3(9)3/2
TC = 22.5
e) For such policy total cost will be -
TC = 1/2(6)2 + 2/3(6)3/2
TC = 27.79
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