1.
If a firm's profit is given by π = -150 + 360Q - 36Q2 , then its optimal output is
a. |
36 units. |
|
b. |
2 units. |
|
c. |
20 units. |
|
d. |
12 units. |
|
e. |
5 units. |
2.
For a good that has a price elasticity of demand of -1.5 and a marginal cost of $50 per unit, the profit-maximizing price should be
a. |
$50 |
|
b. |
$150 |
|
c. |
$200 |
|
d. |
$168 |
|
e. |
$134 |
3.
If dπ/dQ = 0, how do we know if we have a maximum point as opposed to a minimum point?
a. |
The second derivative must also equal zero for it to be a maximum point. |
|
b. |
The second derivative must be negative. |
|
c. |
None of the above |
|
d. |
The second derivative must be positive. |
|
e. |
The second derivative must be between -1 and +1. |
1)
= - 150 + 360Q - 36Q2
d/dQ = 360 - 72Q
put d/dQ = 0
360 - 72Q = 0
360 = 72Q
Q = 360/72
Q = 5
SOC
d2/dQ2 = - 72 < 0
So optimal output is Q = 5
(e) is the correct option.
2)
Ed = - 1.5
MC = 50
Profit maximising condition
MR = MC
P(1 - 1/|Ed|) = MC
P(1 - 1/|-1.5|) = 50
P(1 - 1/1.5) = 50
P(1 - 2/3) = 50
P/3 = 50
P = 150
Profit maximising price is $ 150
(b) is the correct option.
3)
If d/dQ = 0 and to have a maximum point
The second derivative must be negative that is d2/dQ2 < 0
(b) is the correct option.
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