The normal approximation of the binomial distribution is
A. np 10
B. n(1–p) 10
C. np ≤ 10
D. np(1–p) ≤ 10
E. np 10 and n(1–p) 10
Answer to the question:
Option E: np = 10 and n(1–p) = 10.
Explanation: The binomial distribution is approximate by normal distribution if both np and n(1-p) is atleast greater or equal to zero. Here, where p is the probability of success and the (1-p)=q is the probability of failure. Since, both np=nq=10>5, this is the normal approximation of the binomial distribution.
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