Question

The estimated model is Ahe ​= −13.8666 ​+ 1.0217​Age, R2​= 0.121 (0.368​) Where the number in...

The estimated model is

Ahe ​= −13.8666 ​+ 1.0217​Age, R2​= 0.121

(0.368​)

Where the number in parentheses is the homoskedastic standard error for the regression coefficient β1. Using the sample of high school​ graduates, suppose you wanted to test the hypothesis that β1 equals zero at the​ 5% significance level. That​ is,

H0: β1=0 vs. H1: β1≠0

Report the t​-statistic and p​-value for this test. The t​-statistic is ____

College Distance
Ahe Age College
12.6102 34 1
17.2572 25 1
4.0307 32 1
26.146 33 1
33.352 27 1
8.9155 27 1
64.6712 26 1
9.3487 26 1
44.0298 30 1
8.1751 31 1
24.4249 26 1
16.0365 31 1
31.7643 26 1
32.8926 33 1
25.9257 29 1
26.8499 30 1
22.6707 30 1
14.4586 27 1
15.6864 27 1
55.2604 32 1
27.1889 29 1
38.0335 31 1
28.1463 26 1
14.3612 31 1
15.8709 30 1
29.2048 28 1
45.106 34 1
23.4888 27 1
18.44 33 1
27.2437 25 1
39.4441 27 1
14.2008 30 1
22.896 33 1
31.9338 27 1
17.7686 28 1
25.2584 27 1
36.9844 33 1
17.4559 32 1
24.827 31 1
25.9448 34 1
9.3946 31 1
24.5044 34 1
36.0618 29 0
13.5713 28 0
8.0061 26 0
20.0158 29 0
45.4987 33 0
7.2858 27 0
11.9818 33 0
18.1214 25 0
7.6007 32 0
12.5471 29 0
16.9855 28 0
15.1409 29 0
6.7083 27 0
22.2952 33 0
12.148 30 0
8.2473 28 0
15.0424 27 0
6.7796 25 0
16.8188 25 0
14.8258 30 0
15.7019 25 0
2.6229 30 0
23.8469 31 0
12.2451 31 0
21.8335 33 0
15.4616 26 0
32.2909 29 0
10.7363 28 0
11.2132 34 0
14.9038 28 0
24.3312 29 0
12.9998 30 0
17.0164 26 0
9.7228 25 0
10.2584 28 0
18.4956 29 0
11.1666 33 0
18.4905 29 0
15.8924 34 0
17.4147 29 0
17.99 29 0
12.807 25 0
9.8222 29 0
4.0649 25 0
7.177 25 0
9.2321 31 0
19.2232 30 0
12.0358 25 0
22.8428 29 0
20.2687 26 0
14.0444 30 0
8.7165 25 0
31.0064 33 0
7.6344 26 0
16.8722 31 0
12.7747 28 0
23.2383 30 0
16.8357 30 0

Homework Answers

Answer #1

H0: β1=0 vs. H1: β1≠0

As we can see that B1^ = 0.74879

T statistics =( B1^ - B1)/ SE(B1)

T statistics =( 0.74879 - 0 )/ 0.399

T statistics = 0.74879 / 0.399 = 1.87

Also P value of B1^ is given by 0.06399 as shown in table . So P value is greater than 5 % significance level . So we fail to reject the null hypothesis .

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