Suppose an investor plans to make monthly deposits into an account that pays 9% interest, compounded monthly, so that $100,000 will be in the account immediately after the payment at the end of Year 10. The first payment will occur at the end of Month 1 (one month from the present). How much must be deposited monthly
As per the information given in the question
The interest rate of interest given by the account (r) =9% =0.09 compounded monthly
Thought the interest is compounded monthly so compounding period (M) =12 then the required monthly interest rate (i) = r/M = 0.09/12 = 0.0075 =0.75%
Though the investor plans to make monthly deposit (A) for 10 years so the number of interest bearing period (N)= 12x10 = 120 months
Future worth of the deposit at the end of 10 year (F)= $100000
The required monthly deposit (A) = ?
A= F(A/F,i,N)
A = $100000(A/F,0.75%,120)
A=F[i/{(1+i)N-1}]
A=$100000[0.0075/{(1+0.0075)120-1}]
A=$100000[0.0075/{(1.0075)120-1}]
A=$100000(0.0051675773)=$516.7577 or Approx $516.76
The required monthly deposit in that account is (A) = $516.76
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