Use an 8 year project life and a 15% MARR to determine which alternative should be selected. Use the present worth criteria.
A |
B |
|
First Cost |
$5,300 |
$10,700 |
Net Annual Benefit |
$1,800 |
$2,600 |
Salvage Value |
$3,000 |
$3,200 |
Useful Life in years |
4 |
8 |
Please solve by hand, i am not allowed to use excel
The present worth of alternative A = - $ 5300 + $ 1800 1.151 + + $ 1800 1.152 + + $ 1800 1.153 + + $ 1800 1.154 + $ 3,000 1.154
The present worth of alternative A = $ 1554.22
As we are considering 8 years life, the present worth would be $ 1554.22 * 2 = $ 3,108.44
________________________________________________________
The present worth of alternative B = - $ 10,700 + $ 2600 1.151 + $ 2600 1.152 + $ 2600 1.153 + $ 2600 1.154 + $ 2600 1.155 + $ 2600 1.156 + $ 2600 1.157 + $ 2600 1.158 + $ 3200 1.158
Present worth of alternative B = $ 2013.12
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