Question

In a particular year, 40% of home sales were partially financed by the seller. A random...

In a particular year, 40% of home sales were partially financed by the seller. A random sample of 250 sales was examined. What is the probability that 115 or fewer of the 250 homes were partially financed by the seller?

Homework Answers

Answer #1

P = 0.4 (% of home sales)

n = 250 (sample)

X = 115

X/ n = 115/ 250

         = 0.46

Mean = 0.4

This is normal approximation to the binomial.

Standard deviation = √ (pq/ n)

                                = √ (0.4*0.6/250)

                                 = 0.030984

Z = (p-q)/ se(p^)

    = (0.46-0.4)/0.0309838668

      =1.9364916

P (Z>1.9364916) = 0.0264

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