In a particular year, 40% of home sales were partially financed by the seller. A random sample of 250 sales was examined. What is the probability that 115 or fewer of the 250 homes were partially financed by the seller?
P = 0.4 (% of home sales)
n = 250 (sample)
X = 115
X/ n = 115/ 250
= 0.46
Mean = 0.4
This is normal approximation to the binomial.
Standard deviation = √ (pq/ n)
= √ (0.4*0.6/250)
= 0.030984
Z = (p-q)/ se(p^)
= (0.46-0.4)/0.0309838668
=1.9364916
P (Z>1.9364916) = 0.0264
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