Brett and Carl are playing chicken in their cars. If they both stay straight they will be horribly disfigured in a car accident, but both are hoping the other guy swerves so they can be the stronger man who stays straight. They have gotten so close that it is effectively a simultaneous move game. The table shows their possible payoffs, where the contents of each cell are (Brett’s payoff, Carl’s payoff).
Carl's option 1 | Carl's option 2 | ||
Keep Straight | Swerve | ||
Brett's option 1 | Keep Straight | (-10 , -10) | ( 1, -1) |
Brett's option 2 | Swerve | (-1 , 1) | (0 , 0) |
a. Do either/both Brett and Carl have dominant strategies?
b. Does this game have one or more pure strategy Nash equilibriums?
If so, what is/are it/they?
c. Is there a mixed strategy Nash equilibrium? If so, what is
it?
Ans for a)
No neither of the players have any dominant strategy here in this game
Ans for b)
Yes this game has 2 Pure Nash Equilibrium and they are as follows
(Keep Straight,Swerve) & (Swerve, Keep Straight)
Becasue these are PSNE from which no player has profitable deviation to play away from it
Ans for c)
We have 2 NE then we cn find Mixed strategy Nash Equilibrium
Lets assume Brett plays Swerve with prob (1-p) and Carl plays swerve with prob (1-q)
then we need to find value of p and q for which Brett and Carl is indifferent between any of his two strategies
therefore we have
-10q+1*(1-q)=-1*q+0(1-q)
-10q+1-q=q
1/12=q similarly for Brett we can find values of p
-10p+1(1-p)=-1*p
p=1/12
Therefore MSNE are (11/12,1/12) and (11/12,1/12) respectivelt for Brett and Carl
Hence this game has 2 PSNE and 1 MSNE
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