Question

An experiment has been conducted for four treatments with eight blocks. Complete the following analysis of variance table (to 2 decimals, if necessary and p-value to 4 decimals). If your answer is zero enter "0".

Source of Variation	Sum of Squares	Degrees of Freedom	Mean Square	F	p-value
Treatments	900
Blocks	400
Error
Total	1,700

Answer 1

Solution:-

Number of Block(r) = 8

Number of treatment (k) = 4

The complete ANOVA table be:

Source of Variance	Sum of Squares	Degrees of Freedom	Mean Square	F	P Value
Treatment	900	k-1 = 4-3 = 3	900/3 =300	MST/MSE = 300/14.29=20.99	0.0000* [For df1=3, df2=21]
Blocks	400	r-1 = 8-1 = 7	400/7 = 57.14	MSB/MSE =57.14/14.29= 4.00
Error	1,700-(900+400) = 1700-1300 = 400	(r-1)*(k-1) =(4-1)*(8-1) = 3*7 = 21	400/21 = 19.05
Total	1,700	3+ 7 +21 = 31

*The P- Value for test of treatment for (3,21) degrees of freedom is P-value = P(F>Fr) = 0.0000 is equivalent to 0.