Suppose the graph below shows the benefit to a commercial fishery given reductions in N loads. What is the marginal benefit received from increasing N reductions from 400,000 to 500,000lbs?
Quantity of N reductions (lbs) | Total Fishery Benefits |
0 | 0 |
100,000 | $1,000,000 |
200,000 | $1,800,000 |
300,000 | $2,400,000 |
400,000 | $2,700,000 |
500,000 | $2,900,000 |
600,000 | $3,000,000 |
700,000 | $3,050,000 |
$2,900,000
$5.8 per pound of N reduced
$2.9 per pound of N reduced
$2,00 per pound of N reduced
Suppose the graph below shows the benefit to a commercial fishery given reductions in N loads and the total cost to reduce N loads to a particular waterbody (assume an improved fishery is the only benefit of N reduction). What total N load reduction would maximize net benefits to society (TB-TC)?
Total Q of N reduction | Total Fishery Benefits | Total N Abatement Cost |
0 | 0 | 0 |
100,000 | $1,000,000 | $300,000 |
200,000 | $1,800,000 | $700,000 |
300,000 | $2,400,000 | $1,250,00 |
400,000 | $2,700,000 | $2,300,000 |
500,000 | $2,900,000 | $4,300,000 |
600,000 | $3,000,000 | $8,300,000 |
700,000 | $3,050,000 | $18,300,000 |
a)100,000
b)200,000
c)300,000
d)400,000
e) 500,000
f) 600,000
g) 700,000
(1)
The correct answer is (d) $2 per pound of N reduced
Formula Marginal Benefit = Change in Total Benefit / Change in Output
Total Benefit from Producing 400,000 reductions = 2,700,000
Total Benefit from Producing 500,000 reductions = 2,900,000
Hence Change in Total Benefit = 2,900,000 - 2,700,000 = 200,000
Change in Output =500,000 - 400,000 = 100,000
Hence,marginal benefit received from increasing N reductions from 400,000 to 500,000lbs
= 200,000/100,000 = 2
Hence, the correct answer is (d) 2 per pound of N reduced
(2)
The correct answer is (c) 300,000
We can see from above that TB - TC increases till N = 300,000 and after that it starts decreasing. Hence TB - TC is maximum for N = 300,000.
Maximum net benefit = 2,400,000 - 1,250,000 = 1150000
Hence the correct answer is (c) 300,000
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