4. a. For the following total profit function of a firm, where X and Y are two goods sold by the firm:
Profit = 196X – 6X2 –XY -5Y2 +175Y -270
(a) Determine the levels of output of both goods at which the firm maximizes total profit.
(b) Calculate the profit. (20 points)
To work problem 4 you will need to
a. Find the partial derivative (see p. 106) with respect each of the variables. Remember that when taking the partial derivative with respect to a variable that the other variable is treated as a constant; e.g., the partial derivative with respect to X of the expression V = 20XY is 20Y
b. You want to find the quantities at each partial derivative (i.e., each marginal profit) are simultaneously zero. You solve these by simultaneous equations (pp, 107-108) or using substitution (pp. 108-109). Either way works but the substitution is usually the simplest.
4. b. Do problem 4. a. again, but this time with a constraint of X + Y =25. (20 points)
a. To work problem 4. b. use the constraint equation to find an equation for X in terms of Y (X = 40 – Y) or an equation for Y in terms of X.
b. Substitute the equation into the total profit equation at every place you find X (or Y)
c. Set the derivative equal to zero and solve for X (or Y)
d. Plug the result from part c into the constraint equation to get the other variable.
4a:
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4b.
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