Question

In C++ Using recursion write a program that takes a positive integer number and returns whether there is 6. For example, if the input number is 7068, the function returns true

Answer 1

#include <iostream>

using namespace std;

bool has_6(int n) {
    if (n == 0) {
        return false;
    } else if (n % 10 == 6) {
        return true;
    } else {
        return has_6(n / 10);
    }
}

int main() {
    int n;
    cout << "Enter a positive integer: ";
    cin >> n;
    cout << boolalpha << has_6(n) << endl;
    return 0;
}