Question

One way to represent a very large integer (one that won't fit
into

a variable of type short, int, or even long) is to use an
array.

The array is of type int, so each element in the array can
hold an

integer -- we will store just one digit of our number per
array element.

So if a user entered 2375, it might be stored as

--------------------------

| 2 | 3 | 7 | 5 | ... |

--------------------------

(Note that we may want to actually store it right justtified,
with

leading 0's on the left, or maybe in reverse order -- but it
is a

requirement of this program that you get the digits of the
number

from the user 1 at a time, and store them 1 at a time, 1 per
array element.)

You should get a number (into an array) using a function
called GetNumber.

Keep track of how big it is, if need be. Only allow digits
0-9, no

negatives.)

(you'll call it twice, to get 2 numbers to work with.)

Then call another function called AddNumbers. It takes the 2
numbers and

creates another number (stored in another array) that is the
sum of

the 2 given numbers. It should also give back a piece of info
that is

boolean (true/false) -- is the 3rd number "valid" ? (no if the
addition

causes overflow -- it's too big to fit in an array we
use.)

Then call another function called SubNumbers. It takes the 2
numbers and

subtracts them (first minus second.) It gets back to the
calling function

the result (and a boolean telling if it is/isn't valid -- if
it underflows --

the subtraction would yield a negative, the boolean is false,
otherwise

it is true.)

The main function should print out the results (or call a
PrintResults

function if you like.)

Allow the user to run for multiple datasets, as usual.

Note that you MUST use functions for GetNumber, AddNumbers,
and SubNumbers.

Any other functions are optional -- write them if you feel
they help

make this easier.

Make your physical array size 10. (It needs to be exactly 10
to make

the data below, in some instances, meaningful with respect to
testing

underflow/overflow.)

-------------------------------------------------------------------------

Data to test/run (note that I'm listing the numbers as
multi-digit here,

but they MUST be input 1 digit at a time, and stored 1 digit
per array

element.)

9999999999

1

1234567899

8765432101

8765432101

1234567899

2468357955

8000000001

1000000000

1

1000

1

756

437

Answer #1

#include<iostream>

using namespace std;

int * getno(int n)

{

int a[10],value;

int no=n;

for(int i=0;i<10;i++)

a[i]=0;

for(int i=9;i>=0 && no!=0;i--)

{

value=no%10;

no=no/10;

a[i]=value;

}

return a;

}

bool addno(int *a,int *b)

{

int c[10],r,carry=0,n;

for(int i=9;i>=0;i--)

{

c[i]=a[i]+b[i]+carry;

if(c[i]>9)

{

n=c[i];

r=n%10;

n=n/10;

c[i]=r;

carry=n;

}

if(c[0]>9)

break;

}

if(c[0]>9)

return false;

else

return true;

}

bool subno(int *a,int *b)

{

int c[10],flag=0;

int borrow;

for(int i=9;i>=0;i--)

{

if(a[i]<b[i])

{

a[i]=a[i]+10;

a[i-1]=a[i-1]-1;

}

c[i]=a[i]-b[i];

if(a[0]<b[0])

{

flag=1;

break;

}

}

if(flag==1)

return false;

else

return true;

}

int main()

{

long long int n,m;

cout << "\nenter any two nos:";

cin>>n>> m;

int *a=getno(n);

int *b=getno(m);

cout<< "first no is:";

for(int i=0;i<10;i++)

cout<< a[i];

cout<< "\n";

for(int i=0;i<10;i++)

cout<< b[i];

if(addno(a,b))

cout<< "\ntwo nos can be added :)";

else

cout<< "\noverflow";

if(subno(a,b))

cout<< "\ntwo nos can be subtracted:)";

else

cout<< "\nunderflow";

return 0;

}

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