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Operating Systems. In round robin scheduling, Tq=8 milliseconds. Assume that there are n processes running, and...

Operating Systems.

In round robin scheduling, Tq=8 milliseconds. Assume that there are n processes running, and that the worst-case waiting time to get the CPU again is Tw=112 milliseconds. Calculate the number of processes n. (show the calculation)

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Answer #1

Tq(Time Quantum) = 8ms.

This means each process will run for 8 ms and go and join the ready queue if it has to execute more onto CPU.

For worst case, suppose the last process run @ t=112ms

Therefore the nth process, (n-1) process will run and each will run for 8 ms.

Let this n-1 process be y.

So,

y*8 = 112

y = 14

So total number of process is 14+1 = 15

So here when 14 process first execute for 8ms each , the last process ie 15th process will have to wait for 112 ms.

Thus total number of process is 15.

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