SOLUTION-
a. For the symmetric cipher every pair of person must have their key . So in total no. of keys in symmetric cipher=
No. of pairs of people in the organisation.
= NC2
Here no. of people is N= 100
So no. of keys required = 100C2
= 100! / (2!(100−2)!)
= 4950
b. In assymetric cipher every person must have their own private key and public key.
So organisation needs 2 keys per person to make communication secure.
So, in assymetric cipher ,
No. of keys = 2* no. of people in orgnisation
= 2 * N
= 2* 100
= 200.
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