Question

TO BE DONE IN PYTHON: Write a function `lowest_integer()` which takes 2 input arguments:

1)a function `g` representing an increasing function g(x)

2) a number `gmin`,

and returns an integer `nmin` such that nmin>0

is the smallest integer that satisfies g(nmin)>gmin.

test:

def g(n):
    return 2*n
print(lowest_integer(g, 10))

Output: 6

Answer 1

code in python (code to copy)

def lowest_integer(g, num):
    # Initialize the nmin value to 1
    nmin=1
    # loop until g(nmin) is less than or equal to num
    while(g(nmin)<=num):
        # increment nmin each time
        nmin=nmin+1
    # return nmin as the result
    return nmin

def g(n):
    return 2*n
print(lowest_integer(g, 10))

code screenshot

sample console output screenshot