Question

urgent:

1. Consider a 5-bit floating point representation based on the IEEE floating point format with one sign bit, the next two bits of the exponent (exponent bias is 1), and the last two bits of the significand. Fill in the table below. For column M and Value, your answer must be expressed as a fraction of the form x/4.

Bits	M	E	Value
0 01 00
0 01 01
0 01 10
0 01 11
0 10 00	1	4/4	8/4
0 10 01
0 10 10
0 10 11

Answer 1

Ans:

here we are given bits in the form of s ee mm

where s=sign , e= exponent , m=mantissa

Note here Bias=2^{no_exponent_bits-1} -1 = 2^1-1= 2⁰ =1

The required form is value =(1.m)*2^{e -bias}

here, mantissa =1.m

exponent=e-bias = e-1 (or) e-01

Bits	M	E	Value
0 01 00	1.00=1	01-01=0=0/4	1.00*20=1 =4/4
0 01 01	1.01=1.25	01-01=0=0/4	1.01*20=1.25 =5/4
0 01 10	1.10=1.5	01-01=0=0/4	1.10*20=1.50 =6/4
0 01 11	1.11=1.75	01-01=0=0/4	1.11*20=1.75 =7/4
0 10 00	1	4/4	8/4
0 10 01	1.01=1.25	10-01=1=4/4	1.01*21=2.5 =10/4
0 10 10	1.10=1.50	10-01=1=4/4	1.10*21=3 =12/4
0 10 11	1.11=1.75	10-01=1=4/4	1.11*21=3.5 =14/4