Question

Fill in the code for the function below called containsAvgValue. It takes as input a float array of any length and returns 1 if the array happens to contain a value that equals the average of all the values in the array or 0 otherwise. For example, when give the array [2.0, 2.0] it should return 1 since the average value is 2.0 and the array contains that value. To help you, I’ve included a function that computes the average of a float array.

float calcAverage(float x[ ], int len)
{
     /*CODE NOT SHOWN
      FUNCTION RETURNS THE AVERAGE
      OF THE VALUES IN ARRAY X. LEN IS THE
      LENGTH OF X.*/

...

}

    (float x[ ], int len)
{
               float avg;
                = calcAverage(x,  );
               int i;
               int retval;
               retval=0;   

                i = 0;
                while(i<  )
                {
                          if(  ==  )
                          {
                                         =1;
                          }
                          i = i +1;
                }

                return  ;

}

Answer 1

If you have any problem with the code feel free to comment.

Program

#include <stdio.h>

float calcAverage(float x[ ], int len)
{
    float sum =0.0;
    //calculating sum
    for(int i=0; i<len; i++)
    {
        sum += x[i];
    }

    //calculating average of the array
    float avg = sum / len;

    //checking if the array contains its average
    for(int i=0; i<len; i++)
    {
        if(avg == x[i])
            return 1;
    }

    return  0;
}

int main()
{
    float x[] = {2.0, 2.0};

    //testing the method
    if(calcAverage(x, 2) == 1)
        printf("Array contain its average");
    else
        printf("Array does not contain its average");
    printf("\n");

    return 0;
}

Output