Question

(C++ program) Use the code segment below to answer the two questions that follow.

…

int size = 0;
cout << “Enter size: “;

cin >> size;

int sizeCode = size / 10;

if (sizeCode == 0)

   cout << “extra small”;

else if(sizeCode == 1 )

   cout << “small”;

else if (sizeCode == 2)

   cout << “medium”;

else if (sizeCode == 3)

   cout << “large”;

else

   cout << “extra large”;

//end if

…

What would the code display when the size variable contains the value 35?

What would the code display when the size variable contains the value 9?

Rewrite the code in part a above using the switch statement. The new code should have the same functionality as the previous one.

Answer 1

the code display when the size variable contains the value 35 is
large

the code display when the size variable contains the value 9 is
extra small

the code in part a above using the switch statement is
int size = 0;
cout << “Enter size: “;
cin >> size;
int sizeCode = size / 10;
switch(sizeCode){
    case 0:
        cout << “extra small”;
        break;
    case 1:
       cout << “small”;
       break;
    case 2:
        cout << “medium”;
        break;
    case 3:
       cout << “large”;
       break;
    default:
        cout << “extra large”;
}