Question

I am trying to figure out how to find the most common word length in the british dictionary. I have inputted the text file for the british dictionary into my program. I tried a tedious way, but it doesn't seem effective. Can someone help me?

String longestWord = "";

       int maxLength =0;

       int count1 =0, count2 =0, count3=0, count4=0, count5=0, count6=0, count7=0, count8=0, count9=0, count10=0;

       Scanner scanFile = new Scanner (new File("BritishDictionary.txt"));

       ArrayList<String> book = new ArrayList<String>();

       while(scanFile.hasNext())

       {

           book.add(scanFile.next());

          

           for(int i =0; i<= book.size()-1;i++)

           {

               if(book.get(i).length()>longestWord.length())

               {

                   maxLength = book.get(i).length();

                   longestWord = book.get(i);

                  

               }

              

           }

           for(int i =0; i<= book.size()-1; i++)

           {

               if(book.get(i).length() == 2)

               {

                   count1++;

               }

               if(book.get(i).length()==3)

               {

                   count2++;

               }

               if(book.get(i).length()==4)

               {

                   count3++;

               }

               if(book.get(i).length() == 5)

               {

                   count4++;

               }

               if(book.get(i).length() == 6)

               {

                   count5++;

               }

               if(book.get(i).length() ==7)

               {

                   count6++;

               }

               if(book.get(i).length() ==8)

               {

                   count7++;

               }

               if(book.get(i).length()==9)

               {

                   count8++;

               }

               if(book.get(i).length() ==10)

               {

                   count9++;

               }

               if(book.get(i).length()==11)

               {

                   count10++;

               }

           }

       }

       scanFile.close();

       System.out.println("The longest word is:" + longestWord);

      

Answer 1

Hi buddy, please find the below java program

import java.util.*;
import java.lang.*;
import java.io.*;

class Main
{
   public static void main (String[] args) throws java.lang.Exception
   {
       // Scanner object to read the Input file
       Scanner scanFile = new Scanner (new File("BritishDictionary.txt"));
       //HashMap to store count of strings of certain lengths
HashMap<Integer,Integer> hm = new HashMap();
int wordLength=0,maxCount = 0;
while(scanFile.hasNext()){
String str = scanFile.next();
int l = str.length();
if(!hm.containsKey(l)){
hm.put(l,0);
}
//Add the length to the map
hm.put(l,hm.get(l)+1);
}
Set<Integer> key = hm.keySet();
//Iterate through all the elements in the map and find the element
//With most number of occurances
for(Integer x : key){
if(hm.get(x)>maxCount){
maxCount = hm.get(x);
wordLength = x;
}
}
System.out.println("The most common word length is:" + wordLength);
   }
}

INPUT :

a a a adf afd
fd a dfsd adf df df f adf bdf cdf edf

OUTPUT :

The most common word length is:3