Question

Show a conditional expression that returns either a double or an int. Provide an int catch handler and a double catch handler. Show that only the double catch handler executes regardless of whether the int or the double is returned.

Answer 1

#include <iostream>
using namespace std;
//function to execute conditional expression
double Number_exception(int n1,int x,double n2,double y)
{
  if(n1>x)
  {
    return n1;
  }
  else
  {
    return x;
  }
  if(n2>y)
  {
    return n2;
  }
  else
  {
    return y;
  }
}
int main() {
  int n1,x;
  double n2,y;
  //n1 is the value to check with x
  cout<<"Enter value of n1:\n";
  cin>>n1;
  cout<<"Enter value of x:\n";
  cin>>x;
  //n2 is the value to check with y
  cout<<"Enter value of n2:\n";
  cin>>n2;
  cout<<"Enter value of y:\n";
  cin>>y;
  //calling a function to execute conditional expression
  double result= Number_exception(n1,x,n2,y);
  //try block
  try{

    throw result;  //throwing a exception
  }
  catch(int ex)  //int type exception caught
  {
    cout<<"int exception caught";
  }
  catch(double ex) // //double type exception caught
  {
    cout<<"double exception caught";
  }

  
}

Output::

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