Question

Run the below code and shift binary left and right and understand the output. #include <stdio.h>...

Run the below code and shift binary left and right and understand the output.

#include <stdio.h>

int main()

{

    int num=212, i;

    for (i=0; i<=2; i++)

        printf("Right shift by %d: %d\n", i, num>>i);

     printf("\n");

     for (i=0; i<=2; i++)

        printf("Left shift by %d: %d\n", i, num<<i);   

   

     return 0;

}

Output:
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Homework Answers

Answer #1

Output :

Right shift by 0: 212
Right shift by 1: 106
Right shift by 2: 53

Left shift by 0: 212
Left shift by 1: 424
Left shift by 2: 848

Explanation :

At first the for loop will iterates from the 0 to 2:

At first i = 0

num >> i = 212 >> 0 (212 / 20)

= 212

i = 1 :

num >> i = 212 >> 1 (212 / 21)

= 106

i = 2 :

num >> i = 212 >> 2 (212 / 22)

= 53

The second loop will starts executing from i = 0 to 2 (Left shift operations)

At first i = 0

num >> i = 212 >> 0 (212 * 20)

= 212

i = 1 :

num >> i = 212 >> 1 (212 * 21)

= 424

i = 2 :

num >> i = 212 >> 2 (212 * 22)

= 8484

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