Question

Create a MIPS program where you ask a user for 10 digit base 28 number and output a decimal in mips programming. It should also ignore any character that is not in the base 28 system and count its value as 0.

Example:

Input: 100000xza!

Output: 17210368

Input: xyzxyzxyzx

Output:0

Input: 1000000000

Output: 17210368

Output: 10578455953408

Input: 0000000000

Output:0

Answer 1

.data
ms1_msg:.asciiz ""
.text
.globl main
main:

la $a0,ms1_msg    
li $v0,4
syscall

li $v0,5          #user enters number and it is stored in t0
syscall
move $t0,$v0


addi $t1,$zero,1  #t1=1
addi $t2,$zero,2  #t2=2
add $t5,$zero,1   #t5=1
add $t8,$zero,$zero 

add $t6,$zero,$t0  #t6=1

loop1:            #trying to find the counter for loop 2

addi $t5,$t5,1    
div $t0,$t2       
mflo $t4          
beq $t4,$t1,loop2 
sub $t0,$t0,$t0   
loop2:            #twith using the counter (t5) I define how many times loop should circle. 

    addi $t9,$t9,1    
    div $t6,$t2       
    mfhi $t7          
    mflo $t8          
    move $a0, $t7     
    li $v0, 1
    syscall
    beq $t9,$t5,exit
    sub $t6,$t6,$t6   
    add $t6,$t8,$t6 
    j loop2           

    exit:                                      
    li $v0,10       
    syscall
add $t0,$t4,$t0
j loop1