Question

Declare an integer array of size 10 with values initialized as follows.

int intArray[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};

Compute each item of a new array of same size derived from the above array by:

adding first item (intArray[0]) of the array with 3rd, 2nd with 4th, 3rd with 5th and so on. For the last-but-one item intArray[8], add it with first item and for the last item (intArray[9]) add it with 2nd item (treat it as a circular array).

Print all items of the new array in a single line.

Answer 1

#include <iostream>

using namespace std;

int main() {
    int intArray[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};

    int n1 = intArray[0], n2 = intArray[1], size = 10;
    for (int i = 0; i < size-2; ++i) {
        intArray[i] += intArray[i+2];
    }
    intArray[size-1] += n1;
    intArray[size-2] += n2;

    for (int i = 0; i < size; ++i) {
        cout << intArray[i] << " ";
    }
    cout << endl;
    return 0;
}