Question

Problem 1. (1 point) The SolEc algorithm shown below is used with a = 0, b = 2 and n = 3. What is the value of c on the line Write c?

Function z <- f (x)

z = 85−99x + 15x2 − x3;

End Function

algorithm SolEc

Read a, b, n;

For i From 1 To n Do

c = (a + b) / 2;

Write a, ",", c, ",", b;

If f (a) * f (c) <0 Then

b = c;

If not

a = c;

End yes

End To Write c;

End Algorithm

c =

Answer 1

Here,

1)Function z <- f (x)

2)z = 85−99x + 15x2 − x3;

3)End Function

4)algorithm SolEc

5)Read a, b, n;

6)For i From 1 To n Do

7)c = (a + b) / 2;

8)Write a, ",", c, ",", b;

9)If f (a) * f (c) <0 Then

10)b = c;

11)If not

12)a = c;

13)End yes

14)End To Write c;

15)End Algorithm

In line 6) , The loop executes 3 times:

and final value of c= (0 + 2)/2 =1

Then program prints:

0,1,2

For , f(a) , programs goes to function call, with x=0; and returns 85 as f(a).

For , f(b) , programs goes to function call, with x=2; and returns 0 as f(b).

So f(a) * f(b) = 0 which is not less than 0.

So, else part of if statement gets executed. i.e. a=c = 1

So, The value of c on Line Write c is 1.

Hope you find this helpful.

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