Question

Given the following array, add the each element corresponding to its position to form a new array in array1: (In-direct Addressing)

.data

array1 DWORD 0A1223D48h, 11DE33ABh, 11223344h

array2 WORD 0FFFFh, 0A123h, 556Ch

.code

Answer 1

#include<iostream.h>

#include<condo.h>

#include<iomanip.h>

void main()

{

int a[50],i,pos,ele,n;

clrscr();

cout<<"enter the no"<<endl;

cin>>n;

cout<<"enter the elements";

for(i=0;i<n;i++)

cin>>a[i];

cout<<"enter the search element";

cin>>ele;

pos=-1;

for(i=0;i<n;i++)

if(ele==a[i])

{

if(pos>=0)

cout<<"the elements"<<ele<<"is present at position"<<endl;

else

cout<<"the search elements"<<ele<<"is not present''<<endl;

getch();

}