Question

public static void main(String[] args) {

//Given the following code :

int[][] array2D = {{3, 4, 5, 1}, {3,6,1,2}, {1,3,6,5};

Answer :

1- All values ​​of array2D are automatically 0 ? Yes or No

2- What is the value of array2D [3] .length ?________

3-  The value that array2D.length shows is 12: Yes or No ?

4- Assign the value of 12 to the element in the third row, fourth column :

5- the value obtained when calculating array2D [1] [1] + array2D [2] [3] is?

Answer 1

Solution 1:
No. Because array2D array is already specified with elements.

Solution 2:

For array2D[3].length will give you ArrayIndexOutOfBoundException. Because array is of length of three, it will starts from zero index, so the highest index will be two.

Solution 3:

No, the length is 3.

length to determine the number of rows in a 2D array because the length of a 2D array is equal to the number of rows it has.

Solution 4:

public class Main
{
   public static void main(String[] args) {
       int[][] array2D = {{3, 4, 5, 1}, {3,6,1,2}, {1,3,6,5}};
       array2D[2][3]=12;
       System.out.println(array2D[2][3]);
       }
}

Solution 5:

The value is 18.

public class Main
{
   public static void main(String[] args) {
       int[][] array2D = {{3, 4, 5, 1}, {3,6,1,2}, {1,3,6,5}};
       array2D[2][3]=12;
       System.out.println(array2D [1] [1] + array2D [2] [3]);
       }
}