Question

Please, write a loop to print even numbers of an array a with pointers. You can use a variable “size” for array size

Answer 1

#include <stdio.h>

int main() {
    int a[] = {5, 9, 2, 3, 1, 6};   // array for testing
    int size = 6;   // size of the array
    // let's print the array using pointers as asked
    int *p = a; // make p point to first item in array
    int i = 0;
    for (i = 0; i < size; ++i) {    // let's iterate a loop size times
        if (*p % 2 == 0)    // if the number is even, then
            printf("%d ", *p);  // print the number that p is pointing to
        p++;    // move to next element in the array
    }
    printf("\n");   // print a newline
    return 0;
}