Question

Use Boolean algebra to simplify the following expression to obtain the minimum cost implementation: ( !x * !y * !w) + ( !x * !y * z) + ( !x * z * !w) + ( y * !z * w) + ( x * !y * !z)

Answer #1

Eliminate the exclusive OR and simplify the following Boolean
expression to get a minimum POS.
Z= A' · (B⊕C')+AC+B'C

Using Boolean
algebra, derive the minimum SOP expression for the
expression A’B’C+A’BC+ABC. please show the step by step derivation
of the expression

f(a,b,c) =
Xm(0,1,5)
Use boolean algebra to simplify both of the above expressions to
determine the minimal sum-of-products and the minimal
product-of-sums representation for the above function.

Simplify the following Boolean functions, using K-maps. Find all
the prime implicants, and determine which are essential:
(a) F (w, x, y, z) = ? (1, 4, 5, 6, 12, 14, 15)
(b) F (A, B, C, D) = ? (2, 3, 6, 7, 12, 13, 14)
(c) F (w, x, y, z) = ? (1, 3, 4, 5, 6, 7, 9, 11, 13, 15)

Use the properties and theorems of Boolean algebra to reduce the
following expressions to
AND-OR expressions without parentheses. The expressions may not be
unique. Construct the
truth table, which will be unique, by inspection of your final
expression.
g) (a ⊕ b) ⊕ c
i ) (a + b)(a′ + c)(b′ + c′)

Find the truth table (function table), SOM, POM, and
simplify the expression using K Map approach of the following Sigma
notation expression: (10 points) f(w,x d y,z)= sum
m(0,3,9,10,14,15)

Simplify this expression
Q = (x+y’+z)(x+y’+z’)(x’+y+z)(x’+y’+z)
D = (x’+y’+z’)(x’+y+z’)(x’+y+z)

simplify the following boolean expresions by use of k map
a'b' + bc + a'bc'
p'qr + pq'r' + pq'r
xy' + x'y

Convert the following expression to SOP form
F= (W+X) Y*Z) (W+YXX*Y*Z)

Using the algebraic manipulation, Simplify the following
expression
Y = (A + B)(A + C' )(B' + C' )

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