Question

store -9 in 2's complement form utilizing two bytes

Answer 1

two bytes = 2*8 = 16 bits

-9
This is negative. so, follow these steps to convert this into a 2's complement binary
Step 1:
Divide 9 successively by 2 until the quotient is 0
   > 9/2 = 4, remainder is 1
   > 4/2 = 2, remainder is 0
   > 2/2 = 1, remainder is 0
   > 1/2 = 0, remainder is 1
Read remainders from the bottom to top as 1001
So, 9 of decimal is 1001 in binary
So, 9 in normal binary is 0000000000001001
Step 2: flip all the bits. Flip all 0's to 1 and all 1's to 0.
   0000000000001001 is flipped to 1111111111110110
Step 3:. Add 1 to above result
1111111111110110 + 1 = 1111111111110111
so, -9 in 2's complement binary is 1111111111110111

Answer: 1111111111110111