Question

Write a smallest_gap(start_num, end_num) function that finds smallest gap between successive primes, considering prime numbers in the range from start_num to end_num (inclusive).

For example, start_num = 5 and end_num = 12, the prime numbers in that range are: [5, 7, 11]. The smallest gap between any two prime numbers in this list is 2, so the function would return 2.

Some example test cases (include these test cases in your program):

>>> print(smallest_gap(5, 12))

2

# The primes between 1000 and 1020 are 1009, 1013, 1019 so the smallest gap

# is 4 as 1013 – 1009 = 4

>>> print(smallest_gap(1000,1020))

4

In PyCharm

Answer #1

def smallest_gap(start_num, end_num): lst = [] for n in range(start_num, end_num + 1): is_prime = n > 1 for i in range(2, n): if n % i == 0: is_prime = False if is_prime: lst.append(n) min_gap = None for i in range(1, len(lst)): if min_gap is None or lst[i] - lst[i - 1] < min_gap: min_gap = lst[i] - lst[i - 1] return min_gap# Testing the function here. ignore/remove the code below if not required print(smallest_gap(5, 12)) print(smallest_gap(1000, 1020))

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