Question

A) write a program the computes n^x and store the result into y

You can use y = Math.pow( Mantissa, exponent)

Requirements:
Besides main() your program must have one method with two parameters, one double and one int

n and x are positive numbers read from the keyboard
if the user makes an entry that does not meet this criteria, the user must be given to opportunity retry the entry

the user must be able to quit prior to entering values for n and x

Your method must compute y and return the result to its caller; the caller will print the result

After printing the result, the user must be queried again if there are other values to compute; if the answer is no exit the program, but if the user replies yes, then repeat the computation

Answer 1

Here is the required solution in java

here is the code

import java.util.*;
public class Main
{
   public static void main(String[] args) {
   Scanner sc=new Scanner(System.in);
   String s="yes";
   while(true)
   { //taking user input
   System.out.println("Enter value of Mantissa:");
   double Mantissa=sc.nextFloat();
   //input validation
   while(Mantissa<0)
   {
   System.out.println("Invalid input!.Enter again");
   Mantissa=sc.nextFloat();
   }
   System.out.println("Enter value of exponent:");
   int exponent=sc.nextInt();
   while(exponent<0)
   {
   System.out.println("Invalid input!.Enter again");
   exponent=sc.nextInt();
   }
   //call the method
   double result=fun(Mantissa,exponent);
   //print Result
       System.out.println("Result is :"+result);
       //check if user wants to continue or not
       System.out.println("Enter yes to continue or no to exit:");
       s=sc.next();
       if(s.equals("no"))
       break;
   }
   }//method defination to return Mantissa to the power exponent
   public static double fun(double Mantissa,int exponent)
   {
   return Math.pow(Mantissa,exponent);
   }
}