Question

write a loop to print an array a with pointers backwards. You can use a variable “size” for array size. write you code in C

Answer 1

#include <stdio.h>

int main() {
    int n1 = 3, n2 = 9, n3 = 2, n4 = 4, n5 = 1;
    // arr here is an array of pointers
    int *a[5] = {&n1, &n2, &n3, &n4, &n5};

    // printing the array backwards
    int i = 0, size = 5;
    for (i = size - 1; i >= 0; --i) {
        printf("%d ", *a[i]);
    }
    printf("\n");
    return 0;
}

#include <stdio.h>

int main() {
    int a[] = {3, 9, 2, 4, 1}, size = 5;

    // printing the array backwards
    int *p = a + size - 1;
    while (p >= a) {
        printf("%d ", *p);
        p--;
    }
    printf("\n");
    return 0;
}