Question

In C++

1) Write the function definition that has 1 pass by value integer parameter. The function contains logic to return true if the parameter is even and false if it is not.

2 ) Write a main function that prompts the user for a value, calls the function that you created in step one with the value entered by the user, display "even" if the function return true and otherwise displays "odd"

Answer 1

#include <iostream>

using namespace std;

//function to check passed value is even or not
bool oddEven(int val)
{
if(val%2==0)
return true;
  
return false;
}

int main()
{
//variable declaration
int num;
  
//get user input
cout<<"Enter a number: ";
cin>>num;
  
//function calling and display result
if(oddEven(num))
{
cout<<"even";
}
else
{
cout<<"odd";
}

return 0;
}

OUTPUT:

RUN 1:

Enter a number: 8
even

RUN 2:

Enter a number: 15
odd